Question

A 500 kg crate is pushed horizontally with a force of 1500 N. If the coefficient of friction is 0.25, calculate the acceleration of the crate.

Answer 1

$ma=F-fmg\\a=\frac{F-fmg}{m}=\frac{1500-0.25*500*10}{500} =\frac{1}{2}[\frac{m}{s^2}]$