Respuesta :

Answer:

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{10^{t^{2}}}{100^{t}}[/tex].

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{50^{t^{2}}\cdot 2^{t^{2}}}{25^{0.5\cdot t}\cdot 4^{0.5\cdot t}}[/tex].

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{50^{t^{2}-0.5\cdot t}}{5^{t^{2}-0.5\cdot t}}[/tex].

Step-by-step explanation:

The expression to be evaluated is [tex]100^{t^{2}-0.5\cdot t}[/tex], we find by algebraic means the equivalent expression:

Possibility 1:

[tex]100^{t^{2}-0.5\cdot t}[/tex]

[tex]\frac{100^{t^{2}}}{100^{0.5\cdot t}}[/tex]

[tex]\frac{100^{t^{2}}}{(100^{0.5})^{t}}[/tex]

[tex]\frac{100^{t^{2}}}{10^{t}}[/tex]

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{10^{t^{2}}}{100^{t}}[/tex].

Possibility 2:

[tex]100^{t^{2}-0.5\cdot t}[/tex]

[tex]\frac{100^{t^{2}}}{100^{0.5\cdot t}}[/tex]

[tex]\frac{(50\cdot 2)^{t^{2}}}{(25\cdot 4)^{0.5\cdot t}}[/tex]

[tex]\frac{50^{t^{2}}\cdot 2^{t^{2}}}{25^{0.5\cdot t}\cdot 4^{0.5\cdot t}}[/tex]

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{50^{t^{2}}\cdot 2^{t^{2}}}{25^{0.5\cdot t}\cdot 4^{0.5\cdot t}}[/tex].

Possibility 3:

[tex]100^{t^{2}-0.5\cdot t}[/tex]

[tex]\left(\frac{500}{5} \right)^{t^{2}-0.5\cdot t}[/tex]

[tex]\frac{500^{t^{2}-0.5\cdot t}}{5^{t^{2}-0.5\cdot t}}[/tex]

[tex]100^{t^{2}-0.5\cdot t}[/tex] is not equivalent to [tex]\frac{50^{t^{2}-0.5\cdot t}}{5^{t^{2}-0.5\cdot t}}[/tex].

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