Respuesta :
[tex] {x}^{2} - {15}^{2} = {8}^{2} \\ \\ {x}^{2} - 225 = 64 \\ \\ {x}^{2} = 64 + 225 \\ \\ {x}^{2} = 289 \\ \\ x = 17[/tex]
The value of X would be plus and minus 17 for the fact you got the square root of 289.
[tex] {x}^{2} - {15}^{2} = {8}^{2} \\ \\ {x}^{2} - 225 = 64 \\ \\ {x}^{2} = 64 + 225 \\ \\ {x}^{2} = 289 \\ \\ x = 17[/tex]