Question

PLEASE ANSWER THIS QUESTION CORRECTLY, I’LL GIVE YOU BRANLIEST!It’d be amazing if you could answer my other math questions if you solve this one, thank you.

Answer 1

Answer:

4, 16

Step-by-step explanation:

$a_n = 3a_{n - 2} - a_{n - 1} - 1$

Let's see if it works for a_3:

$a_3 = 3a_{1} - a_{2} - 1$

$a_3 = 3(3) - (4) - 1$

$a_3 = 4$

Yes, it works for a_3.

Now let's calculate a_4.

$a_4 = 3a_{2} - a_{3} - 1$

$a_4 = 3(4) - (4) - 1$

$a_4 = 7$

a_4 is also correct.

Let's calculate a_5.

$a_5 = 3a_{3} - a_{4} - 1$

$a_5 = 3(4) - 7 - 1$

$a_5 = 4$

Let's calculate a_6.

$a_6 = 3a_{4} - a_{5} - 1$

$a_6 = 3(7) - 4 - 1$

$a_6 = 16$

Answer: 4, 16