Question

This high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards
What is the area of one of the semicircles at either end
The school decided to cover the semicircles with grass to create a space for stretching and other activities. How many square yards of grass will the school need to cover the entire circle
What is the distance around one of the semicircles at either end of the soccer field
What is the distance around the inner lane of the track the lane closest to the soccer field

PLEASE HELP!

Answer 1

Answer:

do 70x70=4,900  than do 100 x100=10,000 than add them to gether and you get 10,4900

Step-by-step explanation:

theres 2 sides not just one

Answer 2

Answer:

the area for part 1 is 1924

part 2 is 3848

part 3 is 109

part 4 is 309

Step-by-step explanation:

part 1: A=1/2 pi r^2    d=70

r=70/2 = 35

A=(1/2(pi)(35)^2=1924

part 2: A=(2)(1924) = 3848

part 3: 1/2 pi d

c=(1/2(70)(pi))=109

part 4: =L+L+C    L=100yards

D=100+100+109=309

hope this helps plz give brainiest