The graph formed by equation y= -2/3x+10 will be perpendicular to the graph by equation y=3/2x-10.
What is the slope of any line?
A line in the form of ax + by + d = 0 will be a linear equation and if we convert it into the form of y = mx + c where m will be the slope of that equation.
If two lines are perpendicular to each other then the product of their slope of them will be (-1).
⇒ m₁ ₓ m₂ = -1
The slope of line 2x + 3y = 10 will be -2/3
To be any line perpendicular whose slope m with the 2x + 3y = 10
⇒ -2/3 × m = -1
⇒ m = 3/2 so the slope of that line should be 3/2
Hence, line y=3/2x-10 will be perpendicular to the 2x + 3y = 10.
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