Answer:
x = [tex]\frac{\sqrt{12} }{3}[/tex]12 = 8[tex]\sqrt{3}[/tex]
y = [tex]\frac{\sqrt{3} }{3}[/tex]12 = 4[tex]\sqrt{3}[/tex]
Let me know if you need some help simplifying the expressions or o the trig side of things
Step-by-step explanation:
I'm not sure if this is full out trig or recognizing special triangles, specifically 30-60-90 triangles. Of course since one angle is 30 degrees and the other is 90 degrees this is a 30-60-90 triangle.
with 30-60-90 tringles the basic guide is as follows.
The three legs will be referred to as the hypotenuse, short leg and long leg. I will use H, S and L.
H = 2S = [tex]\frac{\sqrt{12} }{3}[/tex]L
S = .5H = [tex]\frac{\sqrt{3} }{3}[/tex]L
L = [tex]\frac{\sqrt{3} }{2}[/tex]H = S[tex]\sqrt{3}[/tex]
If this is trig just break out the unit circle and SOH CAH TOA
So x is the hypotenuse, and y is the short leg and we know the long leg is 12, so we can use that.
to find the hypotenuse knowing the long leg we use H = [tex]\frac{\sqrt{12} }{3}[/tex]L and to find the short leg with the long leg you use S = [tex]\frac{\sqrt{3} }{3}[/tex]L. now just plug in 12 for L
