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let the first number be represented by x and the second 10+3x
x+3x+10=70                                           10+3x=10+3(15)=10+45=55
4x+10=70                                            the two numbers are 15 and 55
4x+10-10=70-10
4x=60
4x/4=60/4
x=15

The two numbers are 15 and 55.

We have two numbers such that the second of two numbers is 10 more than 3 times the first and their sum is 70.

We have to find these two numbers.

Let the first number be x and the second number be y.

Define a linear equation in two variables.

An equation of the form ax + by + c = 0 such that a, b, c are real in nature and the coefficients of the variables x and y are not zero.

According to the question -

y = 3x + 10               (Eqn. 1)

and

x + y = 70    which gives   y = 70 - x

Substituting the value of y in the Eqn. 1, we get -

70 - x = 3x + 10

4x = 60

x = 15

Therefore - y = 70 - 15 = 55

Hence, the two numbers are 15 and 55.

To solve more questions on linear equations in two variables, visit the link below -

https://brainly.com/question/14304114

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