Question

Identify the value of p for the parabola.
$y-5=\frac{1}{16} (x-3)^{2}$

Answer 1

I think it’s 5.2 or 5.1

Answer 2

A parabola is a group of points inside a plane that are equidistant from the focus, as well as a straight line or directrix.

Parabola:

• An idea would be to write its equation in the form of  $y = a(x-h)^2+K$and then discover its friction coefficient using the coordinates of its vertex.
• To find this same value of the coefficient, use the coordinates of its vertex (maximum point, or minimum point).

$\to y-5=\frac{1}{16} (x-3)^2$

The formula for the parabola:

$\to y = a(x-h)^2 + k$

Solving the above-given equation:

$\to y=\frac{1}{16} (x-3)^2+5$

Compare the value and write the value that is:

$\to$  a = $\frac{1}{16}$

$\to$  h = 3

$\to$  k = 5

Solving the value:

$\to y=\frac{1}{16} (x-3)^2+5$

$\to y=\frac{1}{16} (x^2+9-6x)+5\\\\\to y=\frac{x^2}{16} +\frac{9}{16}- \frac{6x}{16}+5\\\\\to y=\frac{x^2}{16} +\frac{9}{16}- \frac{3x}{8}+5\\\\\to y=\frac{x^2}{16} - \frac{3x}{8}+5 +\frac{9}{16}\\\\\to y=\frac{x^2}{16} - \frac{3x}{8}+\frac{80+ 9}{16}\\\\\to y=\frac{x^2}{16} - \frac{3x}{8}+\frac{89}{16}\\\\ \to 16y=x^2 - 6x+89$

by solving the above expression we get (0, 5.563).

Please find the attached file.

Find out more about the parabola here:

brainly.com/question/13089306