Question

is RATIONAL , IRRATIONAL,NON REAL NUMBERS
$\sqrt{27$
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Answer 1

Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

$\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}$

We know that $\sqrt{3}$ is an irrational number (but a real number), so $3\sqrt{3}$ is the same.

In case we need to prove that $\sqrt{3}$ is irrational, please leave a comment.

Answer 2

The answer is Irrational