The point (3,-1) is on the line by which equation below?
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Answer:
D. y = x - 4
Step-by-step explanation:
Given the following data;
Points (x, y) = (3, -1)
To find the equation of line;
First of all, we would determine the slope of the graph.
Mathematically, slope is given by the formula;
[tex] Slope = \frac{Change \; in \; y \; axis}{Change \; in \; x \; axis} [/tex]
[tex] Slope, m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]
Substituting into the equation, we have;
[tex] Slope, m = \frac {5 - 5}{5 - 5} [/tex]
Slope, m = 1
Generally, the equation of straight line is y = mx + c
Where;
m is the slope.
x and y are the points
c is the intercept.
Substituting the values in order to find the intercept, we have;
Using points (x, y) = (3, -1)
-1 = 1*3 + c
-1 = 3 + c
c = -1 - 3
Intercept, c = -4
Therefore, the equation of line becomes;
y = x - 4.