can someone help me find what the “sin0=“ is for this

Answer:
24/25
Step-by-step explanation:
here's your solution
=> perpendicular = 24
=> base = 7
=> hypotenuse = ?
=> firstly we need to find hypotenuse
=> h^2 = p^2 + b^2
=> h^2 = 24^2 + 7^2
=> h^2 = 576 + 49
=> h^2 = 625
=> h = √625
=> h = 25
now sin thita = perpendicular/hypotenuse
=> 24/25
hope it helps