Question

if the area of the field is 16b^2+60b-100 and one dimension is b+5, what would be the other dimension?

Answer 1

Answer:

$l=16(b-1.25)$

Step-by-step explanation:

Given that,

The area of the field is $16b^2+60b-100$

One dimensions = (b+5)

The field is in the shape of a rectangle whose are is given by :

A = lb

Wher

l is the length or the other dimension

$l=\dfrac{A}{b}\\\\l=\dfrac{16b^2+60b-100}{b+5}\\\\l=\dfrac{(16(b+5)(b-1.25)}{b+5}\\\\l=16(b-1.25)$

So, the other dimension be $16(b-1.25)$.