Question

A model rocket is launched directly upward at a speed of 15 meters per second from a height of 10 meters. The function f(t)=−4.9t2+15t+10, models the relationship between the height of the rocket and the time after launch, t, in seconds. When, in seconds after launch, will the rocket reach its highest point? Round to two decimal places.

Answer 1

Answer:

Step-by-step explanation:

To find the highest point we use t = -b/2a (because that's the equation used to find the maximum of the function which is the maximum height the rocket reaches before heading back down ( aka highest point of the parabola at the turning point)

f(t)  = -4.9t^2 +15 +10

A = -4.9

B  = 15

C=10

Plug it in

-15/2(-4.9)   = 1.53 seconds

(In case you get confused 15 turns negative because b in the equation has a - symbol in front. If you had -15 as B you would put -(-15) making it positive)

Hope this is helpful