A current of 0.75 passes through a flashlight bulb that is connected to a 3.0-V battery. Calculate the bulb's resistance.

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Answer:

4 ohms

Explanation:

Use Ohm's Law: V = IR

V = 3.0 V

I = 0.75 A

Plug thise values into the equation:

3.0 V = (0.75 A) R

---> R = 4 ohms

The resistance of the bulb when a current of 0.75 is passed when connected to 3.0 V battery is 4 ohms.

What is resistance?

Resistance is the opposition to the flow of current through it.

Given is the current passing through the bulb is 0.75 Amperes and the voltage of the battery is 3.0 V, then according to the ohm's law,

V = IR

where R is the resistance of the bulb

3.0 V= 0.75 A× R

R = 4 Ω

The resistance of the bulb is 4 Ω.

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