Question

A girl of mass 50.0 kg sits on the right-hand side of a seesaw at a distance of 3.4 m

from its pivot. Another girl of weight 450 N sits on the left-hand side. At what distance

from the pivot must she sit to balance the seesaw? Use g = 10.0 m/s2​

Answer 1

Answer:

3.78 m on the left side of the seesaw

Explanation:

The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:

(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r

Solve for r, and you get 3.78 on the left side.

Hope this helps!