Question

If f(x) = 12x² - 5 and g(x) = x + 7 find(fºg)(x).
I need help asap please and thank you

Answer 1

Answer:

$(f\circ g)(x)=12x^2+168x+583$

Step-by-step explanation:

We are given the two functions:

$f(x)=12x^2-5\text{ and } g(x)=x+7$

And we want to find:

$(f\circ g)(x)$

This is equivalent to:

$=f(g(x))$

Therefore:

$=f(x+7)$

Then by substitution:

$=12(x+7)^2-5$

Square:

$=12(x^2+14x+49)-5$

Distribute:

$=(12x^2+168x+588)-5$

Simplify:

$=12x^2+168x+583$

Therefore:

$(f\circ g)(x)=12x^2+168x+583$