Question

4. A 990 kg car reduces its velocity from 22 m/s to 13 m/s. Calculate the change in the car's momentum:

Answer 1

Answer:

The change in the car's momentum is equal to -8910 kgm/s.

Explanation:

Given that,

The mass of a car, m = 990 kg

Initial speed, u = 22 m/s

Final momentum, v = 13 m/s

We need to find the change in the car's momentum. The change in momentum of the car is given by :

$\Delt p=m(v-u)\\\\=990\times (13-22)\\\\=-8910\ kg-m/s$

So, the required change in the car's momentum is equal to -8910 kgm/s.