Rod is saving Php2000 in a bank at the end of each month which gives an interest of 1% compounded monthly.How much is the savings og Rod after 2 years? ​

Respuesta :

Answer:

Php2040.38

Step-by-step explanation:

Given

[tex]P = 2000[/tex] --- Principal

[tex]r = 1\%[/tex] --- Rate

[tex]t = 2\ years[/tex] --- Time

[tex]n = 12[/tex] --- monthly

Required

Determine the amount at the end of two years

This is calculated as:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

So, we have:

[tex]A = 2000(1 + \frac{1\%}{12})^{12*2}[/tex]

[tex]A = 2000(1 + \frac{1}{100*12})^{24}[/tex]

[tex]A = 2000(1 + \frac{1}{1200})^{24}[/tex]

[tex]A = 2000(\frac{1200+1}{1200})^{24}[/tex]

[tex]A = 2000(\frac{1201}{1200})^{24}[/tex]

[tex]A = 2000*1.02019[/tex]

[tex]A = 2040.38[/tex]

Hence, the final amount is: Php2040.38

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