Question

The temperature at 6:006:00 a.m. was ‐3.5°C‐3.5°C. From 6:006:00 to 7:007:00, the temperature increased 2.5°C2.5°C. From 7:007:00 to 8:008:00, it decreased by 0.25°C0.25°C, and from 8:008:00 to 11:0011:00, the temperature dropped 3.25°C3.25°C. Which expression shows the temperature in °C°C at 11:0011:00 a.m.?

Answer 1

-4.5°C

-3.5°C plus 2.5°C minus .25°C minus 3.25°C

Answer 2

Answer:

-4.75 degree celsius

Step-by-step explanation:

We have to find  the temperature at 11:00 am

Temperature at 6:00 am =-3.5 degree celsius

Temperature increased from 6:00 to 7:00 by = 2.5 degrees celsius

Temperature at 7:00=-3.5+2.5=-1. degree celsius

The temperature decreased from 7:00 to 8:00 by =-0.25 degree celsius

Temperature at 8:00=-1.-0.25=-1.25 degree celsius

Temperature dropped from 8:00 to 11:00 by =3.35 degree celsius

Hence we take -3.5 degree celsius

Then the temperature at 11:00 am =-1.25-3.5=-4.75 degrees celsius