Question

-x^2+4x-8
axis of symmerty​

Answer 1

Answer:

$\boxed {\boxed {\sf x=2}}$

Step-by-step explanation:

The axis of symmetry can be calculated using the formula:

$x=\frac{-b}{2a}$

First we must determine a and b from the quadratic: $-x^2+4x-8$. This is in standard form, with the highest power first in descending order.

Standard form is also: $ax^2+bx+c$

If we compare this to the quadratic given, we can conclude that:

$a= -1 \\b= 4 \\c= -8$

Substitute the values for a and b into the formula.

$x= \frac{-(4)}{2(-1)}$

Multiply in the denominator.

$x=\frac {-4}{-2}$

Divide.

$x=2$

This can also be determined from the graph. It is the x-coordinate of the vertex or the maximum/minimum. It divides the quadratic into 2 symmetrical halves.