Answer (assuming it can be point-slope form):
[tex]y-3=6(x-1)[/tex]
Step-by-step explanation:
Use the point-slope formula [tex]y-y_1 = m (x-x_1)[/tex] to write the equation of the line in point-slope form. Substitute [tex]m[/tex], [tex]x_1[/tex], and [tex]y_1[/tex] for real values.
[tex]m[/tex] represents the slope, so substitute 6 in its place. [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of one point the line intersects, so substitute the x and y values of (1,3) into the equation as well. Substitute 1 for [tex]x_1[/tex] and 3 for [tex]y_1[/tex]. This gives the equation in point-slope form:
[tex]y-(3) = 6(x-(1))\\y-3 = 6(x-1)[/tex]
