When attending a movie, patrons are interested in avoiding the pre-movie trivia games, ads, and previews. It is known that the previews begin at the scheduled movie start time and they last between 5 and 15 minutes. Assume that the time of the previews is uniformly distributed. What is the probability that on a given day the previews last between 10 and 12 minutes

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Answer:

0.2 = 20% probability that on a given day the previews last between 10 and 12 minutes

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

It is known that the previews begin at the scheduled movie start time and they last between 5 and 15 minutes.

This means that [tex]a = 5, b = 15[/tex]

What is the probability that on a given day the previews last between 10 and 12 minutes?

[tex]P(10 \leq X \leq 12) = \frac{12 - 10}{15 - 5} = \frac{2}{10} = 0.2[/tex]

0.2 = 20% probability that on a given day the previews last between 10 and 12 minutes