Answer:
See explanation
Explanation:
Infrared spectroscopy is concerned with transitions between vibrational energy levels. Each infrared active vibration leads to a change in dipole moment.
A ketone compound contains the -C=O group whose signal normally occurs at about 1710 cm-1.
A conjugated ketone is one in which the -C=O group is attached to the -C=C group. This leads to delocalization and reduces the electron density of the C=O double bond, which weakens this bond hence lowering the stretching frequency of the -C=O bond from 1710 to about 1680cm-1.
