Question

a) BCD is a straight line.
Triangle ABC is equilateral.
CE = DE
E
Not drawn
accurately
А
320
B
С
Work out the size of angle x.
(4)​

Answer 1

Answer:

x = 46°

Step-by-step explanation:

Since Δ ABC is equilateral then interior angles = 60°

Since CE = DE then Δ CDE is isosceles and the base angles are congruent, so

∠ ECD = $\frac{180-32}{2}$ = $\frac{148}{2}$ = 74°

BCD is a straight line, then the 3 angles on it sum to 180°, that is

60° + 74° + x = 180°

134° + x = 180° ( subtract 134° from both sides )

x = 46°