Question

The length of a rectangle is shown below:


On a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis, two points A and B are shown. The point A is on ordered pair 1, 2, and the point B is on ordered pair negative 2, 2. A straight line joins the points A and B.


If the area of the rectangle to be drawn is 12 square units, where should points C and D be located, if they lie vertically below the line that connects B and A, to make this rectangle?


1. C(−2, −1), D(1, −1)

2. C(−2, −4), D(1, −4)

3. C(−2, −2), D(1, −2)

4. C(−2, −5), D(1, −5)

Answer 1

Answer:

The answer is option A. C(2, −2), D(−1, −2)

Step-by-step explanation:

The length of AB = 3 units

The area of the rectangle to be drawn is 12 square units

So, the width = The area/The length = 12/3 = 4 units

C and D be located vertically 4 units below A and B

So, C and D like the image of A and B with a transformation rule

(x,y) → (x , y-4)

The coordinates of A(-1,2) and B(2,2)

So, C and D are: (-1,-2) and (2,-2)

Answer 2

Answer:

3: C = (-2, -2) and D = (1, -2)

Step-by-step explanation:

firstly lets figure out what we have so far, a line that is 3 units across, to figure out the next two points, lets first figure out the vertical sides

first divide the area (12) of said shape by the known length of the one side, this is done as shown

12 / 3 = 4

this tells us that 4 is the length of the vertical sides, so we are working with a rectangle with a width of 3 units and a height of 4 units

now all we have to do is plot the corners of the rectangle formed

(-2,-2) and (1,-2)

this method can be used to find the two points or the edges of certain shapes with a known volume or area

hope this helps ya out :)