Question

If 0.647 mil of oxygen are used in the burning of propane, how many moles of CO2 are produced

Answer 1

Answer:

1.733 x 10⁻⁴ mole CO₂(g)

Explanation:

Assuming the rxn given is at STP conditions ...

                        C₃H₈             +       5O₂      =>             3CO₂    +    4H₂O

Given:             Excess             =  0.647ml                ?(moles)           -----  

                                          = 0.000647Liters

                                      = 6.47 X 10⁻⁴L/22.4L·mol⁻¹

                                        = 1.733 x 10⁻⁵ mol O₂

moles CO₂ = 3/5(2.89 x 10⁻⁴)mole CO₂ = 1.733 x 10⁻⁵ mole CO₂