Question

Calculate the mass of 1 Mole of Copper(ii) sulfate pentahydrate​

Answer 1

Answer:

200 g CuSO₄ · 5H₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Moles
• Compounds

Organic

• Prefix roots

Reactions

• Salts
• Anhydride Salts
• Hydrates

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 1 mol CuSO₄ · 5H₂O (Copper II sulfate pentahydrate)

Step 2: Identify Conversions

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CuSO₄ - 63.55 + 32.07 + 4(16.00) = 159.62 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

There is 5 moles of water added for every one mole of Copper II Sulfate present.

1. [DA] Set up:                                                                                                     $\displaystyle 1 \ mol \ CuSO_4(\frac{159.62 \ g \ CuSO_4}{1 \ mol \ CuSO_4}) + 5 \ mol \ H_2O(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
2. [DA] Multiply/Divide [Cancel out units]:                                                         $\displaystyle 159.62 \ g \ CuSO_4 + 90.1 \ g \ H_2O$
3. [DA] Add:                                                                                                         $\displaystyle 249.72 \ g \ CuSO_4 \cdot 5H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

249.72 g CuSO₄ · 5H₂O ≈ 200 g CuSO₄ · 5H₂O