A triangle has sides that are 3, 7, and squareroot 57. Is the triangle a right triangle?
![A triangle has sides that are 3 7 and squareroot 57 Is the triangle a right triangle class=](https://us-static.z-dn.net/files/dab/91cab5a92d475bd5adf6967e298974a5.png)
Answer:
my answer is no because for a right angle triangle the sum of the squares of the other two sides is equal to the square of the longest side
3²+7²=9+49=58
(√57)²=57
57≠58 it's not a right angle triangle
assume the sides to be a,b and c
a=3 b=7 c=√57
by Pythagoras theorem
a²+b²=c²
3²+7²=√57²
but 58≠57
hope it's clear