A right circular cone is shown. The base of the cone is a circle with the center at point A. The Distance from point A to point C is 16 inches. The distance from point C to point B is 20 inches.
![A right circular cone is shown The base of the cone is a circle with the center at point A The Distance from point A to point C is 16 inches The distance from p class=](https://us-static.z-dn.net/files/dc9/6f1cbd21dc53298027e0f160137c37f0.jpg)
![A right circular cone is shown The base of the cone is a circle with the center at point A The Distance from point A to point C is 16 inches The distance from p class=](https://us-static.z-dn.net/files/d02/2330d9570ad7424022ded737c3017602.jpg)
![A right circular cone is shown The base of the cone is a circle with the center at point A The Distance from point A to point C is 16 inches The distance from p class=](https://us-static.z-dn.net/files/d10/d39171d8812230db5daaf2b3797dfa77.jpg)
The distance between the point A and B is 12 inches which is the radius of the cone. Thus, The diameter of the cone will be 24 inches.
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
A right circular cone is shown.
The base of the cone is a circle with the center at point A.
The Distance from point A to point C is 16 inches.
The distance from point C to point B is 20 inches.
[tex]|BC|^2 = |AB|^2 + |AC|^2 \\\\|20|^2 = |AB|^2 + |16|^2 \\\\AB = \sqrt{400 - 256}\\\\AB = \sqrt{144} \\\\AB = 12[/tex]
Therefore, the distance between the point A and B is 12 inches which is the radius of the cone.
Thus, The diameter of the cone will be 24 inches.
Learn more about Pythagoras' theorem here:
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