Respuesta :
Answer:
P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated
Step-by-step explanation:
Given the data in the question;
To test whether population proportion p is overstated;
Null hypothesis H₀ : p = (75%) = 0.75
Alternative hypothesis H₁ : = < (75%) < 0.75
now, sample proportion p" = 64 / 100 = 0.64
from the dot plot below, we will determine the p-value for test { P(p" < 0.64)}
so, the number of times p"<0.64 in 150 simulations is 5
Hence; P(p" < 0.64 ) = 5 / 150 = 0.0333
P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated
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This sample provide evidence that the grocery store manager overstated the true proportion P-value = 0.0333.
Given data in the question:
- To test whether population proportion p is overstated;
- Null hypothesis H₀ : p = (75%) = 0.75
- Alternative hypothesis H₁ : = < (75%) < 0.75
Now, sample proportion p" = 64 / 100 = 0.64
From the dot plot below,
- we will determine the p-value for test { P(p" < 0.64)}
- The number of times p"<0.64 in 150 simulations is 5
Therefore:
- P(p" < 0.64 ) = 5 / 150 = 0.0333
- P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated.
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https://brainly.com/question/16437485?referrer=searchResults