Question

A 30.0 uC charge is moved 5.00 m West in an electric field of 4000 V/m pointing 40.0° North of East. What potential difference did the charge move through?

Answer 1

Answer:

20000sin(40) V

Explanation:

Consider component to the east of electric field:

$E_{x} =4000 sin(40)$

The charge move along this component for 5 meter

Potential difference:

$5E_{x} =20000sin(40)$ = 12900 V (corr, to 3 sig,fig.)