AC =using the Distance Formula
A. 10
B. 5
C. 15
![AC using the Distance Formula A 10 B 5 C 15 class=](https://us-static.z-dn.net/files/df9/9d4f84d79eea99fde27dc869fcde2fff.png)
Answer:
√41
Step-by-step explanation:
Here we want to find the value of AC
A = (-4,0)
C = (1,4)
The distance formula is;
D = √(y2-y1)^2 + (x2-x1)^2
D = √(4-0)^2 + (1-(-4)^2
D = √4^2 + 5^2
D = √(16+25)
D = √41