According to the following reaction, how many moles of barium chloride will be formed upon the complete reaction of 0.307 moles hydrochloric acid with excess barium hydroxide?

hydrochloric acid (aq) + barium hydroxide (aq) barium chloride (aq) + water (l)

Respuesta :

Answer:

0.1535mol

Explanation:

the balanced equation is

2HCL + Ba(OH)2 — BaCL2 + 2H2O

from the equation 2moles of hydrochloric acid reacts to give 1mole of barium chloride

i.e

2mol HCL — 1mol BaCL

0.307 mol HCL — 1 ×0.307/2 = 0.1535mol of Bacl

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