Respuesta :
Answer:
d. The bias will remain the same and the variance will increase.
Step-by-step explanation:
Sample size and bias:
800 is still a large sample size, so the bias will remain the same.
Variance:
From a data set of size n with mean M, the variance is given by:
[tex]V = \sum_{i=0}^{n} \frac{(x_i - M)^2}{n}[/tex]
So as we decrease the sample size, variance increases.
So the correct answer is given by option d.
They do have the following relation for a random selection of n elements from a population with a mean of p and variation [tex]\sigma^2[/tex].
[tex]\to \mathbb{E} (\bar{x}) = \mu;\\\\\to Var(\bar{x}) = \frac{\sigma^2}{n}[/tex] (where [tex]\bar{x}[/tex] is the sample mean)
- As a result, [tex]\bar{x}[/tex] is an impartial estimate of the population mean.
- As a result, bias remains 0 and is influenced by sample size changes.
- Its estimator's variance, on the other hand, is inversely proportional to n and hence reduces as sample size increases.
Therefore, the answer is "Option C".
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