Answer:
[tex]\frac{\sqrt[4]{y}}{y} = y^\frac{-3}{4}[/tex]
Step-by-step explanation:
Given
[tex]\frac{\sqrt[4]{y}}{y}[/tex]
Required
Express as: [tex]y^b[/tex]
Express the denominator as [tex]y^1[/tex]
[tex]\frac{\sqrt[4]{y}}{y} = \frac{\sqrt[4]{y}}{y^1}[/tex]
Rewrite the numerator as: [tex]y^\frac{1}{4}[/tex]
[tex]\frac{\sqrt[4]{y}}{y} = \frac{y^\frac{1}{4}}{y^1}[/tex]
Apply law of indices
[tex]\frac{\sqrt[4]{y}}{y} = y^{\frac{1}{4} - 1}[/tex]
Take LCM
[tex]\frac{\sqrt[4]{y}}{y} = y^\frac{1 -4}{4}[/tex]
[tex]\frac{\sqrt[4]{y}}{y} = y^\frac{-3}{4}[/tex]
