Question

A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum height

Answer 1

Answer:

Given

initial velocity (u) =27.030

Force of gravidity g) =9.8

Rtc maximum height Hmix =?

$sln \\ \ hmix = u {}^{2} \div 2g \\ 27.030 \div 2 \times 9 \\ \\ hmix = 38.025m$