Answer:
Let's simplify step-by-step.
3v(7v−2)+3(v2+2v+1)−3v(−5v+3)
Distribute:
=(3v)(7v)+(3v)(−2)+(3)(v2)+(3)(2v)+(3)(1)+15v2+−9v
=21v2+−6v+3v2+6v+3+15v2+−9v
Combine Like Terms:
=21v2+−6v+3v2+6v+3+15v2+−9v
=(21v2+3v2+15v2)+(−6v+6v+−9v)+(3)
=39v2+−9v+3
Answer:
=39v2−9v+
Hope it helps
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Answer:
6v^2 - 3v + 3
Step-by-step explanation:
Use the distributive property to solve the equations. I did them in chunks. 3v(7v - 2) would be 21^2 - 6v, 3(2v + 2v + 1) would be 12v +3, and 3v(-5v + 3) would be 15v^2 + 9v. Then write out the whole equation. (21v^2 - 6v) + (12v + 3) - (15v^2 + 9 v). Work from left to right and combine like terms. (21v^2 - 15v^2 = 6v^2), (-6v + 6v + 6v - 9v = -3v), then 3 would be isolated.
