last question for the night.

Answer:
third option
Step-by-step explanation:
[tex] \frac{16 {x}^{2} }{4x + 24} \div \frac{8 {x}^{2} - 40x}{ {x}^{2} - 36} \\ = \frac{16 {x}^{2} }{4(x + 6)} \times \frac{(x + 6)(x - 6)}{8x(x - 5)} \\ = \frac{16 {x}^{2} }{4} \times \frac{x - 6}{8x(x - 5)} \\ = \frac{x}{1} \times \frac{x - 6}{2(x - 5)} \\ = \frac{x(x + 6)}{2x - 10} [/tex]
hope it helped
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thanks