Answer:
[tex]a = 4 \: [/tex]
[tex]b = 2 \sqrt{2} [/tex]
Step-by-step explanation:
tan 45° = 1
so,
=》
[tex]1 = \frac{b}{2 \sqrt{2} } [/tex]
=》
[tex]b = 2 \sqrt{2} [/tex]
now,
by pythagorus theorem :-
=》
[tex]a {}^{2} = (2 \sqrt{2} ) {}^{2} + (2 \sqrt{2} ){}^{2} [/tex]
=》
[tex]a {}^{2} = 8 + 8[/tex]
=》
[tex]a {}^{2} = 16[/tex]
=》
[tex]a = \sqrt{16} [/tex]
=》
[tex]a = 4[/tex]
