Question

f(x) = 5x^3+ 2x^2 - 90x - 36.

finding all zeros by factoring and explaining the steps

Answer 1

Answer:

f(x)=5x^3-2x^2-90x-36=0

=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0

x^2-18=0/5x-2=0

x^2=18=x=9√2

5x-2=0

x=2/5

zeros are 9√2,2/5