Answer:
The correct answer is "995.22 turns".
Step-by-step explanation:
The given values are:
Magnetic field,
B = 0.50 T
Current,
i = 400 A
Length of solenoid,
L = 8.0 m
As we know,
⇒ [tex]B=\mu_0ni[/tex]
then,
⇒ [tex]n=\frac{B}{\mu_0i}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{0.50}{4 \pi\times 10^{-7}\times 400}[/tex]
⇒ [tex]=\frac{0.50}{5.024\times 10^{-4}}[/tex]
⇒ [tex]=995.22 \ turns[/tex]
