Question

if tanx-cotx=5 then what is the value of tan²x+cot²x​

Answer 1

Answer:

27

Step-by-step explanation:

note that tanx cotx = tanx × $\frac{1}{tanx}$ = 1

Given

tanx - cotx = 5 ( square both sides )

(tanx - cotx)² = 5² = 25 ← expand left side using FOIL

tan²x - 2tanxcotx + cot²x = 25

tan²x - 2 + cot²x = 25 ( add 2 to both sides )

tan²x + cot²x = 27