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Why is the x coordinate undefined in picture 1?
It's not undefined anywhere else on the circle and is only undefined when the radius is 4.1... not when the radius is 4.2 or 4.
Please write an answer that makes me understand and not just know.
Please answer, you can take your time, I'm not in a hurry.
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(I'll give brainiest)
Please be so kind and do not write nonsense in your answers! I just want an explanation... (T_T)
This is my second time posting this question. This time I spent 100 points, last time I spent 30... please answer...
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Why is the x coordinate undefined in picture 1 Its not undefined anywhere else on the circle and is only undefined when the radius is 41 not when the radius is class=
Why is the x coordinate undefined in picture 1 Its not undefined anywhere else on the circle and is only undefined when the radius is 41 not when the radius is class=

Respuesta :

Answer:

This may be a bug in the Graph, lets sole it

(y-5)^2+(x+5)^2=4.1^2

(y-5)^2+(-9.1+5)^2=4.1^2

After Solving, Y=5

and you may use other graphing calculator such as GeoGebra, Mathwy, Photomath, it shows the answer Correctly

Answer:

Step-by-step explanation:

I am not exactly sure why it is undefined, but in my thought process below, I have noticed a trend, and it might help spark some thoughts.

(y-5)² + (x+5)² = r²

r = 4.1

x = -9.1

y = ?

If we try plugging in the known values to solve for y, then...

(y-5)² + (-9.1+5)² = 4.1²

(y-5)² + 16.81 = 16.81

(y-5)² = 0

y-5 = √0

y = 5

Now solving the equation does show that y exists, so maybe it's a domain/range problem. So let's find the domain and range.

The standard form is (x-a)² + (y-b)² = r², so since we have (y-5)² + (x+5)² = r², our (a is -5) and (b is 5) (and r is 4.1)

The domain of a circle is a-r ≤ x ≤ a+r, which gives (-5)-4.1 ≤ x ≤ (-5)+4.1

So our domain is -9.1 ≤ x ≤ -0.9

The range of a circle is b-r ≤ y ≤ b+r, which gives (5)-4.1 ≤ y ≤ (5)+4.1

So our range is 0.9 ≤ y ≤ 9.1

When x = -9.1, it is within the domain.

When y = 5, it is also within the domain.

Which means that the y value should exists.

BUT...

Here's a trend that I have noticed on desmos...

When (y-5)² + (x+5)² = r² and r = 4.1, y is undefined at the domain boundaries of -9.1 and -0.9

When (y-5)² + (x+5)² = r² and r = - 4.1, y is undefined at the domain boundaries of -9.1 and -0.9

When (y-5)² + (x+4)² = r² and r = 4.1, y is undefined at the domain boundaries of -8.1 and -0.1

When (y-4)² + (x+5)² = r² and r = 4.1, y is undefined at the domain boundaries of -9.1 and -0.9

When (y-5)² + (x+6)² = r² and r = 4.1, y is undefined at the domain boundaries of -10.1 and -1.9

When (y-6)² + (x+5)² = r² and r = 4.1, y is defined (y=6) at the domain boundaries of -9.1 and -0.9

When (y-6)² + (x+6)² = r² and r = 4.1, y is defined (y=6) at the domain boundaries of -10.1 and -1.9

When (y-6)² + (x+5)² = r² and r = 8.3, y is undefined at the domain boundaries of -13.3 and 3.3

When (y-6)² + (x+6)² = r² and r = 8.3, y is undefined at the domain boundaries of -14.3 and 2.3

I do not understand the trend despite of spending last night and today thinking about it. But Hope it helps. (If you saw me answering yesterday night, yea that's me, I ended up deleting it cuz I can't think it through, but then I thought that maybe it could help spark your thoughts, so here it is)

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