Answer:
3.85 g Zn
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
[Given] 3.55 × 10²² atoms Zn
[Solve] grams Zn
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Zn - 65.39 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 3.55 \cdot 10^{22} \ atoms \ Zn(\frac{1 \ mol \ Zn}{6.022 \cdot 10^{23} \ atoms \ Zn})(\frac{65.39 \ g \ Zn}{1 \ mol \ Zn})[/tex]
- [DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 3.85477 \ g \ Zn[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
3.85477 g Zn ≈ 3.85 g Zn