Answer:
[tex]2BPO_4+Ca_3N_2\rightarrow 2BN+Ca_3(PO_4)_2[/tex]
Double displacement.
Explanation:
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In this case, according to the reactants, we need to keep in mind that boron has a charge of 3+, phosphate ion a charge of 3-, Calcium 2+ and nitride 3-. Thus, for the double displacement reaction that is analyzed, we obtain:
[tex]BPO_4+Ca_3N_2\rightarrow BN+Ca_3(PO_4)_2[/tex]
Which is balanced to:
[tex]2BPO_4+Ca_3N_2\rightarrow 2BN+Ca_3(PO_4)_2[/tex]
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