Answer:
Explanation: Unbalanced Equation;
Na³SO⁴+PbCl²=NaCl+ Pb³(SO⁴)²
Balanced Equation:
2(Na³SO⁴) +3PbCl²=6NaCl+Pb³(SO⁴)²
Mole ratio:2:3=6:1
Molar mass of Na³SO⁴=3×(23)+32+(4×16)
= 69+32+64
= 69+96=165g/mol
No. of moles in 84.05g of Na³SO⁴
=84.05/165
= 0.51 moles
Using the mole ratio, The number of NaCl moles=0.51×6/2
= 0.51×3
. = 1.53 moles
Mass of NaCl produced. = 1.53×23
= 35.19g
