7. A solution containing 90grams of KNO3 per 100. grams of H2O at
50.°C is considered to be
(1) dilute and unsaturated
(2) dilute and supersaturated
(3) concentrated and unsaturated
(4) concentrated and supersaturated

Respuesta :

Answer:

(4) concentrated and supersaturated

Explanation:

At 50.°C, 90g of KNO3 lies above the solubility curve [on the Regents Reference Table G]. This indicates that the solution is supersaturated, meaning it contains more solute than will naturally dissolve, and was formed when a saturated solution cooled. Furthermore, the percent concentration of this solution is 90% KNO3 making this solution concentrated. This can be calculated using the formula for mass percent concentration.

Percent Mass = Mass of Solute (g) x 100

                         Mass of Solution (g)

Given solution is considered as concentrated and supersaturated.

What is supersaturated solution?

Supersaturated solutions are those solutions in which no. of dissolved solute is more and added to the saturated solution of that solute.

In the question given that,

Weight of solute or KNO₃ = 90 g

Weight of solvent or water = 100 g

Temperature = 50°C

According to the solubility curve, given solution is supersaturated because it contains excess amount of solute and it is concentrated because solute in dissolve in the saturated solution at nearly high temperature and after cooling we get the consistent solution.

Hence, option (4) is correct i.e. given solution is concentrated and supersaturated.

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