Question

48g of methane was burned in an excess of air. What mass of carbon dioxide would be produced in the reaction assuming complete combustion? Use the information below to answer the question.

Answer 1

Answer:

132g

Explanation:

CH4= 12+4=16  

moles= m/Mr    moles=48/16=3 mol

CO2= Mr=44

there are the same number of moles as methane:

Mass= Mrxmoles

44x3=132g