Question

WILL MARK BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION
When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed is
J.____
Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of?
The train can climb a hill that is
m.____high.

Answer 1

Answer:

Kinetic energy = 5400000 J

Height, h = 45.91 m

Explanation:

It is given that,

Mass of the roller coaster train, m = 12,000 kg

Velocity of the train, v = 30 m/s

Kinetic energy is given by :

KE=\dfrac{1}{2}mv^2KE=

2

1

mv

2

KE=\dfrac{1}{2}\times 12000\ kg\times (30\ m/s)^2KE=

2

1

×12000 kg×(30 m/s)

2

KE=5400000\ JKE=5400000 J

So, the kinetic energy of the train at the top speed is 5400000 J.

For height

According to law of conservation of energy :

PEni+KE i=PE f+KE fPE i +KEi

=PEf +KE f

0+5400000\ J=mgh+00+5400000 J=mgh+0

5400000\ J=mgh5400000 J=mgh

h is the height.

5400000\ J=12000\ kg\times 9.8\ m/s^2\times h5400000 J=12000 kg×9.8 m/s

2

×h

h=45.91\ mh=45.91 m

Hence, this is the required solution.